php – regular expression to get all urls in a string except one url

Question

I have an array of urls

urls = [ 'example.co.uk/nz', 'example.com/us', 'exclude.example.co.uk' ];

now I wanted to do some manipulations with the above 2 urls and want to skip the third. here is my code.

function xyz($url) {
     $url_locale = preg_match( '#(.co.uk|.com)/([a-zA-Z]{2})/#', $url, $matches );
     
      if ( ! empty( $matches[2] ) ) {
         // do something
       } else {
         // do something else
      }

   }

xyz( $url[0] ); //do something
xyz( $url[1] ); //do something
xyz( $url[2] ); //do something else

so basically it should exclude the exclude.example.co.uk from the preg_match

0
Ashish rawat 3 months 2022-06-22T02:33:20-05:00 0 Answers 0 views 0

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