How can I get $id variable in widget’s form function?

Question

How can I get $id variable in widget’s form function?
According to widget’s structure I see that widget function have $args as a parameter, which will be extracted in function’s body. In my case i want to use $id variable (from extracted $args) which contains current sidebar’s id. How can I make ‘visible’ $id variable in form function? Any ideas?

class Ex_Widget_Example extends WP_Widget {
    //constructor goes here
    function widget($args, $instance) {extract($args);}
    function update($new_instance, $old_instance ) { }
    function form( $instance ) {}
}

For example we have sidebar with id ‘my_sidebar’. I put this widget in it. For example my widget function, which we use to output something on page, looks like this:

function widget($args, $instance) {
         extract($args);
         echo $id; //or just echo $args['id'];
}

So on my page, in my ‘my_sidebar’ sidebar I will see a text ‘my_sidebar’. That’s great. But how can I get this $id or $args[‘id’] in widget’s form function. In class example I see, that only widget function takes $args as argument. I’m not an expert in OOP pragramming, I tried to create a static variable (unsuccessfully), which would keep id value:

class Ex_Widget_Example extends WP_Widget {
    public static $widget_id;
    //constructor goes here
    function widget($args, $instance) {
             extract($args);
             self::$widget_id = $id;
             echo self::$widget_id //here outputs sidebar's id perfectly on my page
    }
    function update($new_instance, $old_instance ) { }
    function form( $instance ) {
             echo self::$widget_id //here outputs nothing on my widget's form
    }
}

Maybe wordpress call form function first, before widget function, that’s why I can’t see anything on my form ….anyway, any ideas how to solve this problem?

0
, , user13250 10 years 2012-02-20T14:12:30-05:00 0 Answers 98 views 0

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